(x+1)(x-3)+(x+1)^2=0

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Solution for (x+1)(x-3)+(x+1)^2=0 equation: 



(x+1)(x-3)+(x+1)^2=0

We multiply parentheses ..

(+x^2-3x+x-3)+(x+1)^2=0

We get rid of parentheses

x^2-3x+x+(x+1)^2-3=0

We add all the numbers together, and all the variables

x^2-2x+(x+1)^2-3=0

We move all terms containing x to the left, all other terms to the right

x^2-2x+(x+1)^2=3

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